# coordinate geometry formulas pdf class 10

CBSE Class 10 Maths Formulas: Class 10 is the primary gateway for the next level of academics. Candidates who are ambitious to qualify the CBSE Class 10 with good score can check this article for Notes. A collection of questions on CBSE- Coordinate Geometry with solutions created by best teachers are available as a PDF download. Point ‗0‘ is called the origin. To recall, coordinate geometry is the study of geometry using the coordinate points. Free PDF download of Chapter 7 - Coordinate Geometry Formula for Class 10 Maths. This is possible only when you have the best CBSE Class 10 Maths study material and a smart preparation plan. Your email address will not be published. Our team of Math experts have created a list of Class 10 Maths formulas for you with logical explanations as well as the method of how and where to use them. names and positions of other students in your class. 5.2, we get CD = 1 m OD=x - Y2-Y Now, Also, A AFP and x D Log in. The distance formula is one of the important concepts in coordinate geometry which is used widely. Thus, PG 1 m 1 m and m Y2-Y m = IY2 — Iy my — myl ly my — PG mx — mx Ix + mx— — [x + mx [x + mx Let A (x , y ) and B(x , Y2) be two distinct points such that a point P(x, y) divides AB internally in the ratio I : m. That is, From the Fig. Success is said to be the sum of small efforts that are repeated daily and by using this list of important formulas in your exam preparations, you will be able to understand their logic, solve complex problems faster, score higher marks in your school exams and crack various competitive exams! To assist you with that, we are here with notes. Maths Class 10 Notes for Coordinate Geometry THE CARTESIAN CO-ORDINATE SYSTEM Let X‘OX and YOY‘ be two perpendicular straight lines meeting at fixed point 0 then X‘OX is called the x—axis and Y‘OY is called the axis of y or y axis. This formula is known as section formula. In coordinate geometry, the position of a point can be easily defined using coordinates. NCERT Solutions for Class 10 Chapter 7 Coordinate Geometry covers all the exercises provided in the NCERT textbook. x axis is known as abscissa and y—axis is known as ordinate. The distance of the point P (2, 3) from the x-axis is. NCERT Books for Class 10 Maths Chapter 7 Coordinate Geometry can be of extreme use for students to understand the concepts in a simple way.NCERT Textbooks for Class 10 Maths are highly recommended as they help cover the … Chapter 1 Basic Geometry An intersection of geometric shapes is the set of points they share in common. Our FREE CBSE Class 10 chapter-wise formulas PDF covers the following chapters: Download FREE PDF of Formula Sheets for Class 10, \begin{align} {AB = \sqrt {\left( {x_2 - x_1 } \right)^2 + \left( {y_2 - y_1 } \right)^2 } } \end{align}, \begin{align} {\left( {\frac{{mx_2 + nx_1 }}{{m + n}},\frac{{my_2 + ny_1 }}{{m + n}}} \right)} \end{align}, \begin{align} {\left( {\frac{{x_1 + x_2 }}{2},\;\frac{{y_1 + y_2 }}{2}} \right)} \end{align}, \begin{align} \text{ar}(\Delta A B C)=\frac{1}{2} \times \begin{bmatrix}x_{1}(y_{2}-y_{3})+\\x_{2}(y_{3}-y_{1})+\\x_{3}(y_{1}-y_{2})\end{bmatrix} \end{align}, \begin{align} \sin ^2 A + \cos ^2 A = 1 \end{align}, \begin{align} \tan ^2 A + 1 = \sec ^2 A \end{align}, \begin{align} \cot ^2 A + 1 = {\rm{cosec}}^2 A \end{align}, \begin{align} \tan A = \frac{{\sin A}}{{\cos A}} \end{align}, \begin{align} \cot A = \frac{{\cos A}}{{\sin A}} \end{align}, \begin{align} {\rm{cosec}}\,A = \frac{1}{{\sin A}} \end{align}, \begin{align} \sec A = \frac{1}{{\cos A}} \end{align}, \begin{align} \sin \left( {90^\circ - A} \right) = \cos A \end{align}, \begin{align} \cos \left( {90^\circ - A} \right) = \sin A \end{align}, \begin{align} \tan \left( {90^\circ - A} \right) = \cot A \end{align}, \begin{align} \cot \left( {90^\circ - A} \right) = \tan A \end{align}, \begin{align} \sec \left( {90^\circ - A} \right) = {\rm{cosec}}\,A \end{align}, \begin{align} {\rm{cosec}}\left( {90^\circ - A} \right) = \sec A \end{align}, \begin{align} \frac{1}{2} \end{align}, \begin{align} \frac{1}{{\sqrt 2 }} \end{align}, \begin{align} \frac{{\sqrt 3 }}{2} \end{align}, \begin{align} \frac{1}{{\sqrt 3 }} \end{align}, \begin{align} \frac{2}{{\sqrt 3 }} \end{align}, \begin{align} \theta = \frac{{\left( {180 \times l} \right)}}{{\left( {\pi r} \right)}} \end{align}, \begin{align} = \left( {\frac{\theta }{2}} \right) \times r^2 \end{align}, \begin{align}\theta &= \text{Angle between two radii}\\R &= \text{Radius of outer circle}\\r &= \text{Radius of inner circle}\end{align}, \begin{align} {a_m = \frac{{a_1 + a_2 + a_3 + a_4 }}{4} = \frac{{\sum\limits_0^n a }}{n}} \end{align}, \begin{align} {{\rm{Median}} = l + \left( {\frac{{\frac{n}{2} - cf}}{f}} \right)h} \end{align}, \begin{align} {M_o = l + \left( {\frac{{f_1 - f_0 }}{{2f_1 - f_0 - f_2 }}} \right)h} \end{align}, \begin{align} &ax^2 + bx + c = 0\\ &\text{where }a \ne 0 \end{align}, \begin{align} &P(x) = ax^2 + bx + c \\& \text{ where }a \ne 0 \end{align}, The Roots of the Quadratic Equations are zeroes, \begin{align} b^2 - 4ac = 0 \end{align}, \begin{align} {b^2 - 4ac > 0} \end{align}, \begin{align} {b^2 - 4ac < 0} \end{align}, \begin{align} H^2 = AS^2 + OS^2 \end{align}, \begin{align}H&= \text{Hypotenuse}\\AS&=\text{Adjacent Side}\\OS&=\text{Opposite Side}\end{align}, Two corresponding sides and an angle are equal, Two corresponding angles and a side are equal, \begin{align} l \times b \times h \end{align}, \begin{align} 2h\left( {l + b} \right) \end{align}, \begin{align} 2\left( {lb + bh + hl} \right) \end{align}, \begin{align} \frac{4}{3} \times \pi r^3 \end{align}, \begin{align} 4\pi r^2 \end{align}, \begin{align} 4\pi r^2 \end{align}, \begin{align} \pi r^2 h \end{align}, \begin{align} 2 \times \left( {\pi rh} \right) \end{align}, \begin{align} 2\pi r \times \left( {r + h} \right) \end{align}, \begin{align} \frac{1}{3} \times \begin{bmatrix}\text{Area of }\\\text{the Base}\end{bmatrix} \times h \end{align}, \begin{align} \frac{1}{2} \times p \times L \end{align}, \begin{align} {\text{LSA}} + \begin{bmatrix}\text{Area of }\\\text{the Base}\end{bmatrix} \end{align}, \begin{align} \frac{1}{3} \times \left( {\pi r^2 h} \right) \end{align}, \begin{align} \pi r \times \left( {r + L} \right) \end{align}, \begin{align} \frac{2}{3} \times \left( {\pi r^3 } \right) \end{align}, \begin{align} 2\pi r^2 \end{align}, \begin{align} 3\pi r^2 \end{align}, \begin{align} B \times h \end{align}, \begin{align} p \times h \end{align}, \begin{align} \pi \times r \times \left( {r + L} \right) \end{align}, \begin{align} l &= \text{Length, } \\ h &= \text{Height,} \\ b &= \text{Breadth} \\ r &= \text{Radius of Sphere} \\ L &= \text{Slant Height} \end{align}, Chapter-3   Pair of Linear Equations in Two Variables, Chapter-9   Some Applications of Trigonometry.

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